# CCI - Problem 1.5
# Determine whether a string is one edit away from being
# the same as a second string (replace, add, remove)

s1 = input("Enter a string: ")
s2 = input("Enter another string: ")

oneAway = True

# Equal lengths
if (len(s1) == len(s2)):
  count = 0
  for i in range(0,len(s1)):
    if (s1[i] != s2[i]):
      count += 1
  if (count > 1):
    oneAway = False

# Length differs by 1
elif (len(s1)==len(s2)-1 or len(s2)==len(s1)-1):
  if (len(s1) < len(s2)):
    newArray = []
    newArray.append(' ')
    # Copy s1 to new array
    for c in s1:
      newArray.append(c)
    for i in range(0,len(newArray)):
      oneAway = True
      count = 0
      for j in range(0,len(newArray)):
        if(newArray[j] != s2[j]):
          count += 1
      if (count > 1):
        oneAway = False
      else:
        break
      temp = newArray[i]
      newArray[i] = newArray[i+1]
      newArray[i+1] = temp
  
  if (len(s2) < len(s1)):
    newArray = []
    newArray.append(' ')
    # Copy s2 to new array
    for c in s2:
      newArray.append(c)
    for i in range(0,len(newArray)):
      oneAway = True
      count = 0
      for j in range(0,len(newArray)):
        if(newArray[j] != s1[j]):
          count += 1
      if (count > 1):
        oneAway = False
      else:
        break
      temp = newArray[i]
      newArray[i] = newArray[i+1]
      newArray[i+1] = temp
else:
  oneAway = False
if (oneAway == True):
  print("true")
else:
  print("false")



# CCI - Problem 1.5
# Determine whether a string is one edit away from being
# the same as a second string (replace, add, remove)

s1 = input("Enter a string: ")
s2 = input("Enter another string: ")

oneAway = True

# Equal lengths
if (len(s1) == len(s2)):
  count = 0
  for i in range(0,len(s1)):
    if (s1[i] != s2[i]):
      count += 1
  if (count > 1):
    oneAway = False

# Length differs by 1
elif (len(s1)==len(s2)-1 or len(s2)==len(s1)-1):
  if (len(s1) < len(s2)):
    newArray = []
    newArray.append(' ')
    # Copy s1 to new array
    for c in s1:
      newArray.append(c)
    for i in range(0,len(newArray)):
      oneAway = True
      count = 0
      for j in range(0,len(newArray)):
        if(newArray[j] != s2[j]):
          count += 1
      if (count > 1):
        oneAway = False
      else:
        break
      temp = newArray[i]
      newArray[i] = newArray[i+1]
      newArray[i+1] = temp
  
  if (len(s2) < len(s1)):
    newArray = []
    newArray.append(' ')
    # Copy s2 to new array
    for c in s2:
      newArray.append(c)
    for i in range(0,len(newArray)):
      oneAway = True
      count = 0
      for j in range(0,len(newArray)):
        if(newArray[j] != s1[j]):
          count += 1
      if (count > 1):
        oneAway = False
      else:
        break
      temp = newArray[i]
      newArray[i] = newArray[i+1]
      newArray[i+1] = temp
else:
  oneAway = False
if (oneAway == True):
  print("true")
else:
  print("false")



# CCI - Problem 1.5
# Determine whether a string is one edit away from being
# the same as a second string (replace, add, remove)

s1 = input("Enter a string: ")
s2 = input("Enter another string: ")

oneAway = True

# Equal lengths
if (len(s1) == len(s2)):
  count = 0
  for i in range(0,len(s1)):
    if (s1[i] != s2[i]):
      count += 1
  if (count > 1):
    oneAway = False

# Length differs by 1
elif (len(s1)==len(s2)-1 or len(s2)==len(s1)-1):
  if (len(s1) < len(s2)):
    newArray = []
    newArray.append(' ')
    # Copy s1 to new array
    for c in s1:
      newArray.append(c)
    for i in range(0,len(newArray)):
      oneAway = True
      count = 0
      for j in range(0,len(newArray)):
        if(newArray[j] != s2[j]):
          count += 1
      if (count > 1):
        oneAway = False
      else:
        break
      temp = newArray[i]
      newArray[i] = newArray[i+1]
      newArray[i+1] = temp
  
  if (len(s2) < len(s1)):
    newArray = []
    newArray.append(' ')
    # Copy s2 to new array
    for c in s2:
      newArray.append(c)
    for i in range(0,len(newArray)):
      oneAway = True
      count = 0
      for j in range(0,len(newArray)):
        if(newArray[j] != s1[j]):
          count += 1
      if (count > 1):
        oneAway = False
      else:
        break
      temp = newArray[i]
      newArray[i] = newArray[i+1]
      newArray[i+1] = temp
else:
  oneAway = False
if (oneAway == True):
  print("true")
else:
  print("false")



# CCI - Problem 1.5
# Determine whether a string is one edit away from being
# the same as a second string (replace, add, remove)

s1 = input("Enter a string: ")
s2 = input("Enter another string: ")

oneAway = True

# Equal lengths
if (len(s1) == len(s2)):
  count = 0
  for i in range(0,len(s1)):
    if (s1[i] != s2[i]):
      count += 1
  if (count > 1):
    oneAway = False

# Length differs by 1
elif (len(s1)==len(s2)-1 or len(s2)==len(s1)-1):
  if (len(s1) < len(s2)):
    newArray = []
    newArray.append(' ')
    # Copy s1 to new array
    for c in s1:
      newArray.append(c)
    for i in range(0,len(newArray)):
      oneAway = True
      count = 0
      for j in range(0,len(newArray)):
        if(newArray[j] != s2[j]):
          count += 1
      if (count > 1):
        oneAway = False
      else:
        break
      temp = newArray[i]
      newArray[i] = newArray[i+1]
      newArray[i+1] = temp
  
  if (len(s2) < len(s1)):
    newArray = []
    newArray.append(' ')
    # Copy s2 to new array
    for c in s2:
      newArray.append(c)
    for i in range(0,len(newArray)):
      oneAway = True
      count = 0
      for j in range(0,len(newArray)):
        if(newArray[j] != s1[j]):
          count += 1
      if (count > 1):
        oneAway = False
      else:
        break
      temp = newArray[i]
      newArray[i] = newArray[i+1]
      newArray[i+1] = temp
else:
  oneAway = False
if (oneAway == True):
  print("true")
else:
  print("false")



# CCI - Problem 1.5
# Determine whether a string is one edit away from being
# the same as a second string (replace, add, remove)

s1 = input("Enter a string: ")
s2 = input("Enter another string: ")

oneAway = True

# Equal lengths
if (len(s1) == len(s2)):
  count = 0
  for i in range(0,len(s1)):
    if (s1[i] != s2[i]):
      count += 1
  if (count > 1):
    oneAway = False

# Length differs by 1
elif (len(s1)==len(s2)-1 or len(s2)==len(s1)-1):
  if (len(s1) < len(s2)):
    newArray = []
    newArray.append(' ')
    # Copy s1 to new array
    for c in s1:
      newArray.append(c)
    for i in range(0,len(newArray)):
      oneAway = True
      count = 0
      for j in range(0,len(newArray)):
        if(newArray[j] != s2[j]):
          count += 1
      if (count > 1):
        oneAway = False
      else:
        break
      temp = newArray[i]
      newArray[i] = newArray[i+1]
      newArray[i+1] = temp
  
  if (len(s2) < len(s1)):
    newArray = []
    newArray.append(' ')
    # Copy s2 to new array
    for c in s2:
      newArray.append(c)
    for i in range(0,len(newArray)):
      oneAway = True
      count = 0
      for j in range(0,len(newArray)):
        if(newArray[j] != s1[j]):
          count += 1
      if (count > 1):
        oneAway = False
      else:
        break
      temp = newArray[i]
      newArray[i] = newArray[i+1]
      newArray[i+1] = temp
else:
  oneAway = False
if (oneAway == True):
  print("true")
else:
  print("false")