#!/usr/bin/env python
# coding: utf-8
#
2. Add Two Numbers
#
#
#
# You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order, and each of their nodes contains a single digit. Add the two numbers and return the sum as a linked list.
#
# You may assume the two numbers do not contain any leading zero, except the number 0 itself.
#
#
# Example 1:
#
# Input: l1 = [2,4,3], l2 = [5,6,4]
# Output: [7,0,8]
# Explanation: 342 + 465 = 807.
#
#
# Example 2:
#
# Input: l1 = [0], l2 = [0]
# Output: [0]
#
#
# Example 3:
#
# Input: l1 = [9,9,9,9,9,9,9], l2 = [9,9,9,9]
# Output: [8,9,9,9,0,0,0,1]
#
#
#
# Constraints:
#
#
# - The number of nodes in each linked list is in the range
[1, 100]
.
# 0 <= Node.val <= 9
# - It is guaranteed that the list represents a number that does not have leading zeros.
#
#
#
#
# Source
#
# In[1]:
# Definition for singly-linked list.
class ListNode:
def __init__(self, val=0, next=None):
self.val = val
self.next = next
# Code
# In[2]:
def add_two_numbers(l1, l2):
"""iterative approach."""
carry = 0
answer = curr_sol = ListNode(carry)
while l1 or l2 or carry != 0:
tmp = carry
if l1:
tmp += l1.val
l1 = l1.next
if l2:
tmp += l2.val
l2 = l2.next
val = tmp % 10
carry = tmp // 10
curr_sol.next = ListNode(val)
curr_sol = curr_sol.next
return answer.next
#
# Follow up:
# Solve it both recursively and iteratively.
#
# Code
# In[ ]:
def add_two_numbers(l1, l2):
"""recursive approach."""
def helper(l1,l2,carry):
if l1 or l2 or carry != 0:
tmp = carry
if l1:
tmp += l1.val
l1 = l1.next
if l2:
tmp += l2.val
l2 = l2.next
val = tmp % 10
carry = tmp // 10
answer = ListNode(val)
answer.next = helper(l1, l2, carry)
return answer
return None
return helper(l1,l2,0)