The metric is defined by its components in the coordinate frame associated with Boyer-Lindquist coordinates, which is the current manifold's default frame:
# In[9]: rho2 = r^2 + (a*cos(th))^2 Delta = r^2 -2*m*r + a^2 + q^2 g[0,0] = -1 + (2*m*r-q^2)/rho2 g[0,3] = -a*sin(th)^2*(2*m*r-q^2)/rho2 g[1,1], g[2,2] = rho2/Delta, rho2 g[3,3] = (r^2 + a^2 + (2*m*r-q^2)*(a*sin(th))^2/rho2)*sin(th)^2 g.display() #The list of the non-vanishing components:
# In[10]: g.display_comp() #The component $g^{tt}$ of the inverse metric:
# In[11]: g.inverse()[0,0] #The lapse function:
# In[12]: N = 1/sqrt(-(g.inverse()[[0,0]])); N # In[13]: N.display() # ## Electromagnetic field tensor # # Let us first get the 1-forms $(\mathrm{d}t, \mathrm{d}r, \mathrm{d}\theta, \mathrm{d}\phi)$ as those forming # the coframe associated with Boyer-Lindquist coordinates: # In[14]: BL.coframe() # In[15]: dt, dr, dth, dph = BL.coframe()[:] dt, dph # The electromagnetic 4-potential 1-form $A$ of the Kerr-Newman solution is # In[16]: A = - q*r/rho2 * (dt - a*sin(th)^2*dph) A.set_name('A') A.display() # The electromagnetic field tensor $F$ is computed as the exterior derivative of the 4-potential: $F = \mathrm{d} A$. In Sage, the exterior derivative of a $p$-form is returned by the function `diff()`: # In[17]: F = diff(A) F.set_name('F') F.display() # As a check, let us compare with Eq. (33.5) of [Misner, Thorne & Wheeler (1973)](https://press.princeton.edu/books/ebook/9781400889099/gravitation): # In[18]: F == q/rho2^2 * (r^2-a^2*cos(th)^2)*dr.wedge( dt - a*sin(th)^2*dph ) \ + 2*q/rho2^2 * a*r*cos(th)*sin(th)*dth.wedge( (r^2+a^2)*dph - a*dt ) # We can get a short expression of $F$ by factoring the components: # In[19]: F.apply_map(factor) F.display() # The list of non-vanishing components of $F$: # In[20]: F.display_comp() #The Hodge dual of $F$:
# In[21]: star_F = F.hodge_dual(g) star_F.display() #Let us check that $F$ obeys the two (source-free) Maxwell equations:
# In[22]: diff(F).display() # In[23]: diff(star_F).display() #The Levi-Civita connection $\nabla$ associated with $g$:
# In[24]: nabla = g.connection() print(nabla) #Let us verify that the covariant derivative of $g$ with respect to $\nabla$ vanishes identically:
# In[25]: nabla(g) == 0 #Another view of the above property:
# In[26]: nabla(g).display() #The nonzero Christoffel symbols (skipping those that can be deduced by symmetry of the last two indices):
# In[27]: g.christoffel_symbols_display() #The default vector frame on the spacetime manifold is the coordinate basis associated with Boyer-Lindquist coordinates:
# In[28]: M.default_frame() is BL.frame() # In[29]: BL.frame() #Let us consider the first vector field of this frame:
# In[30]: xi = BL.frame()[0] ; xi # In[31]: print(xi) #The 1-form associated to it by metric duality is
# In[32]: xi_form = xi.down(g) xi_form.display() #Its covariant derivative is
# In[33]: nab_xi = nabla(xi_form) print(nab_xi) nab_xi.display() #Let us check that the vector field $\xi=\frac{\partial}{\partial t}$ obeys Killing equation:
# In[34]: nab_xi.symmetrize() == 0 #Similarly, let us check that $\chi := \frac{\partial}{\partial\phi}$ is a Killing vector:
# In[35]: chi = BL.frame()[3] ; chi # In[36]: nabla(chi.down(g)).symmetrize() == 0 #Another way to check that $\xi$ and $\chi$ are Killing vectors is the vanishing of the Lie derivative of the metric tensor along them:
# In[37]: g.lie_derivative(xi) == 0 # In[38]: g.lie_derivative(chi) == 0 # ## Curvature # # The Ricci tensor of $g$: # In[39]: Ric = g.ricci() print(Ric) # In[40]: Ric.display() # We can get a shorter expression by factorizing the components: # In[41]: Ric.apply_map(factor) Ric.display() # A matrix view of the components: # In[42]: Ric[:] #Let us check that in the Kerr case, i.e. when $q=0$, the Ricci tensor is zero:
# In[43]: Ric_Kerr = Ric.copy() Ric_Kerr.apply_map(lambda f: f.subs({q: 0})) Ric_Kerr[:] # ### Riemann tensor # # The Riemann curvature tensor of $g$: # In[44]: R = g.riemann() R.apply_map(factor) print(R) #The component $R^0_{\ \, 101}$ of the Riemann tensor is
# In[45]: R[0,1,0,1] #The expression in the uncharged limit (Kerr spacetime) is
# In[46]: R[0,1,0,1].expr().subs(q=0).factor() #while in the non-rotating limit (Reissner-Nordström spacetime), it is
# In[47]: R[0,1,0,1].expr().subs(a=0).factor() #In the Schwarzschild limit, it reduces to
# In[48]: R[0,1,0,1].expr().subs(a=0, q=0) #Obviously, it vanishes in the flat space limit:
# In[49]: R[0,1,0,1].expr().subs(m=0, a=0, q=0) # ### Ricci scalar # # The Ricci scalar $R = g^{ab} R_{ab}$ of the Kerr-Newman spacetime vanishes identically: # In[50]: g.ricci_scalar().display() #The Einstein tensor is
# In[51]: G = Ric - 1/2*g.ricci_scalar()*g print(G) #Since the Ricci scalar is zero, the Einstein tensor reduces to the Ricci tensor:
# In[52]: G == Ric # The invariant $F_{ab} F^{ab}$ of the electromagnetic field: # In[53]: Fuu = F.up(g) F2 = F['_ab']*Fuu['^ab'] print(F2) # In[54]: F2.display() #The energy-momentum tensor of the electromagnetic field:
# In[55]: Fud = F.up(g,0) T = 1/(4*pi)*( F['_k.']*Fud['^k_.'] - 1/4*F2 * g ) T.apply_map(factor) print(T) # In[56]: T[:] # Check that the Einstein equation is satisfied: # In[57]: G == 8*pi*T #Let us check the Bianchi identity $\nabla_p R^i_{\ \, j kl} + \nabla_k R^i_{\ \, jlp} + \nabla_l R^i_{\ \, jpk} = 0$:
# In[58]: DR = nabla(R) # long (takes a while) print(DR) # In[59]: for i in M.irange(): for j in M.irange(): for k in M.irange(): for l in M.irange(): for p in M.irange(): print(DR[i,j,k,l,p] + DR[i,j,l,p,k] + DR[i,j,p,k,l], end=' ') #If the last sign in the Bianchi identity is changed to minus, the identity does no longer hold:
# In[60]: DR[0,1,2,3,1] + DR[0,1,3,1,2] + DR[0,1,1,2,3] # should be zero (Bianchi identity) # In[61]: DR[0,1,2,3,1] + DR[0,1,3,1,2] - DR[0,1,1,2,3] # note the change of the second + to - # ### Kretschmann scalar # # The tensor $R^\flat$, of components $R_{abcd} = g_{am} R^m_{\ \, bcd}$: # In[62]: dR = R.down(g) print(dR) # The tensor $R^\sharp$, of components $R^{abcd} = g^{bp} g^{cq} g^{dr} R^a_{\ \, pqr}$: # In[63]: uR = R.up(g) print(uR) # The Kretschmann scalar $K := R^{abcd} R_{abcd}$: # In[64]: Kr_scalar = uR['^abcd']*dR['_abcd'] Kr_scalar.display() # A variant of this expression can be obtained by invoking the method `factor()` on the coordinate function representing the scalar field in the manifold's default chart: # In[65]: Kr = Kr_scalar.coord_function() Kr.factor() #As a check, we can compare Kr to the formula given by R. Conn Henry, Astrophys. J. 535, 350 (2000):
# In[66]: Kr == 8/(r^2+(a*cos(th))^2)^6 *( 6*m^2*(r^6 - 15*r^4*(a*cos(th))^2 + 15*r^2*(a*cos(th))^4 - (a*cos(th))^6) - 12*m*q^2*r*(r^4 - 10*(a*r*cos(th))^2 + 5*(a*cos(th))^4) + q^4*(7*r^4 - 34*(a*r*cos(th))^2 + 7*(a*cos(th))^4) ) #The Schwarzschild value of the Kretschmann scalar is recovered by setting $a=0$ and $q=0$:
# In[67]: Kr.expr().subs(a=0, q=0) #Let us plot the Kretschmann scalar for $m=1$, $a=0.9$ and $q=0.5$:
# In[68]: K1 = Kr.expr().subs(m=1, a=0.9, q=0.5) plot3d(K1, (r,1,3), (th, 0, pi), axes_labels=['r', 'theta', 'Kr']) # In[69]: print("Total elapsed time: {} s".format(time.perf_counter() - comput_time0)) # *NB:* most of the computational time is spent in checking the Bianchi identity.