Given a sorted (in ascending order) integer array nums
of n
elements and a target
value, write a function to search target
in nums
. If target
exists, then return its index, otherwise return -1
.
Example 1:
Input:nums
= [-1,0,3,5,9,12],target
= 9 Output: 4 Explanation: 9 exists innums
and its index is 4
Example 2:
Input:nums
= [-1,0,3,5,9,12],target
= 2 Output: -1 Explanation: 2 does not exist innums
so return -1
Note:
nums
are unique.n
will be in the range [1, 10000]
.nums
will be in the range [-9999, 9999]
.Source
def binary_search(nums, target):
pass
nums = [-1,0,3,5,9,12]
target = 9
binary_search(nums, target)
4
nums = [-1,0,3,5,9,12]
target = 2
binary_search(nums, target)
-1
Solve it both iteratively and recursively. Solve it using built-in methods too.
def binary_search(nums, target):
pass