Write a program to compute the frequency of the words from the input. The output should output after sorting the key alphanumerically.
Suppose the following input is supplied to the program:
New to Python or choosing between Python 2 and Python 3? Read Python 2 or Python 3.
Then, the output should be:
2:2
3.:1
3?:1
New:1
Python:5
Read:1
and:1
between:1
choosing:1
or:2
to:1
In case of input data being supplied to the question, it should be assumed to be a console input.
Solutions:
ss = input().split()
word = sorted(set(ss)) # split words are stored and sorted as a set
for i in word:
print("{0}:{1}".format(i, ss.count(i)))
OR
ss = input().split()
dict = {}
for i in ss:
i = dict.setdefault(
i, ss.count(i)
) # setdefault() function takes key & value to set it as dictionary.
dict = sorted(
dict.items()
) # items() function returns both key & value of dictionary as a list
# and then sorted. The sort by default occurs in order of 1st -> 2nd key
for i in dict:
print("%s:%d" % (i[0], i[1]))
OR
ss = input().split()
dict = {
i: ss.count(i) for i in ss
} # sets dictionary as i-> split word & ss.count(i) -> total occurrence of i in ss
dict = sorted(
dict.items()
) # items() function returns both key & value of dictionary as a list
# and then sorted. The sort by default occurs in order of 1st -> 2nd key
for i in dict:
print("%s:%d" % (i[0], i[1]))
OR
from collections import Counter
ss = input().split()
ss = Counter(ss) # returns key & frequency as a dictionary
ss = sorted(ss.items()) # returns as a tuple list
for i in ss:
print("%s:%d" % (i[0], i[1]))
Solution by: AnjanKumarG
from pprint import pprint
p = input().split()
pprint({i: p.count(i) for i in p})
n = int(input())
print(n ** 2)
Python has many built-in functions, and if you do not know how to use it, you can read document online or find some books. But Python has a built-in document function for every built-in functions.
Please write a program to print some Python built-in functions documents, such as abs(), int(), raw_input()
And add document for your own function
The built-in document method is doc
Solutions:
print(str.__doc__)
print(sorted.__doc__)
def pow(n, p):
"""
param n: This is any integer number
param p: This is power over n
return: n to the power p = n^p
"""
return n ** p
print(pow(3, 4))
print(pow.__doc__)
class Car:
name = "Car"
def __init__(self, name=None):
self.name = name
honda = Car("Honda")
print(f"{Car.name} name is {honda.name}")
toyota = Car()
toyota.name = "Toyota"
print(f"{Car.name} name is {toyota.name}")
Car name is Honda Car name is Toyota